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                [HAOI2007]分割矩阵                </h1>
                <p>时间限制：10s&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  空间限制：162MB</p>			</div>
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                                <h3>题目描述</h3><p><p>　　将一个a*b的数字矩阵进行如下分割：将原矩阵沿某一条直线分割成两个矩阵，再将生成的两个矩阵继续如此<br />
分割（当然也可以只分割其中的一个），这样分割了（n-1)次后，原矩阵被分割成了n个矩阵。（每次分割都只能<br />
沿着数字间的缝隙进行）原矩阵中每一位置上有一个分值，一个矩阵的总分为其所含各位置上分值之和。现在需要<br />
把矩阵按上述规则分割成n个矩阵，并使各矩阵总分的均方差最小。请编程对给出的矩阵及n，求出均方差的最小值<br />
。</p></p><hr/><h3>输入格式</h3><p><p>第一行为3个整数，表示a,b,n(1&lt;a,b&lt;=10,1&lt;n&lt;=10）的值。<br />
第二行至第n+1行每行为b个小于100的非负整数，表示矩阵中相应位置上的分值。每行相邻两数之间用一个空<br />
格分开。<br />
</p></p><hr/><h3>输出格式</h3><p><p>仅一个数，为均方差的最小值（四舍五入精确到小数点后2位）</p></p><hr/><h3>样例输入</h3><pre>5 4 4
2 3 4 6
5 7 5 1
10 4 0 5
2 0 2 3
4 1 1 1</pre><hr/><h3>样例输出</h3><pre>0.50</pre><hr/><h3>提示</h3><p>没有写明提示</p><hr/><h3>题目来源</h3><p>没有写明来源</p>
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